# ICSE Class 10th Maths – Value Added Tax MCQs

#### A music system was marked at Rs 20000. If a sum of Rs 1500 was given as discount, then the discount percent is ____.

Marked price = Rs 20000 and discount = Rs 1500

Percentage of discount=1500/20000×100

= 7.5 %

Hence, the discount per cent is 7.5

#### The value of 320 in percentage form is ____.

3/20=3/20×100/100

=3×5/100

=15/100

= 15 %

Hence, the required percentage is 15.

#### The value of 7/4 in percentage form is ____.

7/4=7/4×100/100

=7×25/100

= 175 %

Hence, the required percentage is 175 %.

#### A moped was sold at Rs 13200 after a discount of 12 % on the marked price, then the discount is ____.

Let marked price be x.

Discount = 12 % of M.P.

=12/100×x

=3x/25

We know that,

Discount = Marked price − Sale price

⇒3x/25=x−13200

⇒13200=22x/25

⇒x=13200×25/22

= 600 × 25

x = 15000

Discount =3x/25

=3/25×15000

= 1800

Hence, the discount is Rs 1800.

#### If 80 is 32 % of a certain number, then the number is ____.

Let the number be x.

⇒ 32% of x = 80

⇒32/100×x=80

⇒x=80×100/32

⇒ x = 250

Hence, the required number is 250.

#### In an election between two candidates, one candidate secured 43% of the total votes polled and lost by 4900 votes. The total number of votes polled is ____.

Let the total number of votes polled be 100

The loosing candidate gets 43% of 100 = 43 votes

and, the winning candidate gets = 100−43 = 57 votes

The number of votes by which the loosing candidate has lost the election = 57−43

= 14

When election is lost by 14 votes, the total number of votes polled = 100

When election is lost by 4900 votes, the total number of votes polled =100/14×4900

= 35000

Hence, the total number of votes polled is 35000.

#### In an examination, 30% candidates failed in English, 35% failed in Mathematics and 27% failed in both the subjects. The percentage of total passed is ____.

Let the total number of candidates be 100.

Given, the number of candidates who failed only in English = 30

The number of candidates who failed only in Mathematics = 35

The number of candidates who failed in both = 27

Total number of failures = 30 +35 − 27

= 38

Number of candidates who passed the examination = 100 − 38

= 62

Hence, the percentage of candidates who passed is 62 %.

#### If two numbers are respectively 10 % and 25 % more than a third number, then the first number as a percent of the second is ____.

Let the third number be 100

Given, the first number is 10% more than the third number

⇒The first number = 100 + 10 % of 100

= 110

Given, the second number is 25% more than third number

⇒The second number = 100 + 25 % of 100

= 125

The first number as the percent of the second = 110/125×100

= 88

Hence, the first number as the percent of the second is 88.

#### A dealer allows his customers a discount of 25% and still gains 25%. If an article costs Rs 1,440 to the dealer, then the selling price is ____.

Given, cost price = Rs 1,440 and profit = 25%

Profit =1440×25/100

=1440×1/4

= 360

Selling price = Cost price + Profit

= 1440 + 360

= 1800

Hence, the selling price is Rs 1800.

#### By selling 144 eggs, Anuj lost the S.P. of 6 eggs. His loss percent is ____.

Let S.P. of 1 egg = Rs 1

S.P. of 144 eggs = 144×1

= Rs 144

Loss = S.P. of 6 eggs

= Rs 1× 6

= Rs 6

C.P. of 144 eggs = S.P. + Loss

= 144 + 6

= Rs 150

Loss % = Loss/C.P.×100

= 6/150×100

= 4

Hence, Anuj's loss percent is 4.

#### If a jacket was sold for Rs 680 after allowing a discount of 15% on the marked price, then the marked price of the Jacket is ____.

Let marked price be Rs x.

Discount = 15% on x

=15/100×x

=3x/20

Selling price =x−3x/20

=17x/20

⇒17x/20=680

⇒x=680×20/17

= 800

Hence, the marked price of the jacket is Rs 800.

#### Rakesh purchased a cycle for Rs 660 including sales tax. If the rate of sales tax is 10%, then the original price of cycle is ____.

Let the original price of cycle be Rs x.

Sales tax = 10% of x

= 10/100×x

= x/10

Amount to be paid for the cycle = x + x/10

= 11x/10

⇒11x/10=660

⇒ x = 660×10/11

= 600

Hence, the original price of the cycle is Rs 600.

#### Nazim purchases a motor cycle, having marked price of Rs 46,000 at a discount 5%. If sales tax is charged at 10%, then the amount he has to pay to purchase the motorcycle is ____.

Marked price of motorcycle = Rs 46000.

Discount = 5%

Discounted price of motor cycle = (46000−46000×5/100)

= 46000−2300

= Rs 43700

Sales tax on Rs 43700

= 43700×10/100

= 4370

Amount = 43700 + 4370

= 48,070

Hence, the amount he has to pay to purchase the motorcycle is Rs 48,070.

#### A single discount equivalent to two successive discounts of 10% and 5% is ____.

Let the MP be Rs 100.

1st discount = 10% of 100

= Rs 10

Reduced price = 100 − 10

= 90

2nd discount = 5% of 90

= 5/100× 90

= 4.50

Reduced price = 90 −4.50

= 85.50

Net discount = 100 − 85.50

= 14.50

Discount % =Discount/M.P.×100%

=14.50/100×100%

= 14.5 %

#### A man spends 65 % of his salary and saves Rs 525 per month. The monthly salary of the man is ____.

Let the man's monthly salary be Rs x.

He spends 65 % of x.

Saving = Rs 525 per month

65 % of x + 525 = x

⇒ 525 = x − 65 % of x

=x−65/100×x

=100x−65x/100

⇒525=35x/100

⇒ 35x = 525 × 100

⇒x=525×100/35

=525×20/7

= 75 × 20

⇒ x = 1500

Hence, the monthly salary of the man is Rs 1500.

#### The cost of a machine depreciates every year by 10 % of its cost at the beginning of the year. If the present cost of the machine is Rs 10,000, then the cost after two years is ____.

Given, present cost of the machine = Rs 10000

Depreciation in its cost in 1st year = 10% of Rs 10000

=10/100×10000

= Rs 1000

The cost of the machine after one year = Rs (10000 − 1000)

= Rs 9000

Depreciation in its cost in 2nd year = 10% of Rs 9,000

=10/100×9000

= Rs 900

The cost of the machine after 2nd year = Rs (9,000 − 900)

= Rs 8100

Hence, the cost of the machine after two years is Rs 8100.

#### If a number decreased by 18 % becomes 410, then the number is ____.

Let the number be 100.

Decrease in number = 18 % of 100

= 18

Now, the number becomes = 100 − 18

= 82

When the decreased number = 82, the original number = 100

When the decreased number = 410, the original number =100/82×410

= 500

Hence, the required number is 500.

#### Rakesh's income is 25 % more than Rohan's income. The percentage of Rohan's income less than Rakesh's income is ____.

Let Rohan's income be Rs 100.

Rakesh's income = Rs 125

If Rakesh's income is Rs 125, Rohan's income = Rs 100

If Rakesh's income is Rs 1, Rohan's income = Rs 100/125

If Rakesh's income is Rs 100, Rohan's is income = Rs (100/125×100)

= Rs 80
Difference between Rohan's and Rakesh's income = 100−80

= 20

Hence, Rohan's income is 20% less than that of Rakesh.

#### A number is increased by 10 % and then it is decreased by 10 %. The net per cent is ____.

Let the number be 100.

Increase in the number = 10 % of 100

=10/100×100

= 10

Increased number = 100 + 10

= 110

Decrease in the number = 10% of 110

=10/100×110

=11

New number = 110−11

= 99

Net decrease = 100−99

= 1

Net percentage decrease =1/100×100

= 1

Hence, the per cent decrease is 1 %.

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